2nd Year 1st Sem. Study

Thursday, September 3, 2009

Configuration of Personal Computer

Configuration

Less Expensive Computer

Expensive Computer

Basic Configuration

Product Description

Price

Basic Configuration

Product Description

Price

Processor

Intel Dual Core 2.6 GHz

6000/=

Processor

Intel Core 2 Duo 2.8 GHz

8800/=

Mother Board

AT (Baby)

4500/=

Mother Board

ATX

8700/=

RAM

2 GB DDR-2

1750/=

RAM

2 GB DDR – 3

3700/=

Hard Disk Drive

250 GB SATA

3000/=

Hard Disk Drive

1000 GB ATA

8200/=

Monitor

Samsung 17” CRT

5300/=

Monitor

Samsung 19” LCD

10300/=

Casing

Thermal

1800/=

Casing

Thermal

1800/=

Key Board

Standard

300/=

Key Board

Standard

300/=

Mouse

Optical

300/=

Mouse

Optical

300/=

DVD RW/Combo

Sony DRU – 500A DVD RW

2200/=

DVD RW/Combo

Sony DRX – 500 ULX DVD RW

11300/=

Speaker

Creative (2 way speaker)

1700/=

Speaker

Creative (3 way speaker)

3700/=

UPS

Off line (Samsung)

10300/=

UPS

Line interactive (Sony)

19000/=

Total

37150/=

Total

76100/=

Compare Two Computers

Less Expensive Computer

Expensive Computer

Subject

Description

Subject

Description

Processor

Dual Core has 2 processors. It’s a 32 bit processor & the cache memory is 2 MB.

Processor

Core 2 Duo is 64 bit processor & the cache memory is 4 MB.

Mother Board

There are different variations in AT design. The Baby AT design mother board can usually fit inside a Baby AT case or full AT case.

Mother Board

ATX design uses a different power supply connector and ATX case cools internal components much more efficiently then predecessor.

Graphics Card

It is attached with mother board. PCI cards can access the memory available on the actual card.

Graphics Card

It is attached with mother board. AGP cards can access the system memory to help with complex operations.

RAM

DDR – 2 RAM reduce heat and consumption at higher speeds.

RAM

DDR – 3 RAM runs at higher clock speed as mentioned.

DVD RW/Combo

Sony DRU – 500 A

Data transfer rate: 33.3 mb/s MAX

Random access time: 160 ms (CD-ROM)

200ms (DVD-ROM)

Buffer memory: 8MB

DVD RW/Combo

Sony DRX – 500 ULX

Data transfer rate: 480 mb/s

MAX

Random access time: 160 ms (CD-ROM)

200ms (DVD-ROM)

Buffer memory: 8MB

Hard Disk Drive

SATA = Serial ATA

Smaller connections & higher data speeds.

Hard Disk Drive

ATA = Advanced Technology Attachment and has speeds of up to 133 Mbps, has a 40 pin connector.

UPS

“Offline” UPS are connected via an electrical relay. In normal operation, the electrical voltage is used to recharge the batteries.

UPS

“Line Interactive” are part of hybrid technology. Indeed, the line connected in parallel via relay but has a micro-processor monitoring the voltage continuously.

Sunday, July 19, 2009

Matrix Application

Quiz-3

Following is the input-output table:

Agriculture(Sale)

Industry(Sale)

Final Demand

Agriculture(Purchase)

3

4

3

Industry(Purchase)

6

10

4

· Find the disposition of sectors’ outputs.

· Find the transaction matrix.

· Find the direct requirement matrix(input-output co-efficient matrix)

· Find the direct and indirect requirement matrix(input output co-efficient matrix)

· What will be the gross production if the demand of the agriculture and industry sector were 8 and 12 respectively?

Solution:

a. Disposition of output of the sectors’ and final output

Total Input Output Table

Agriculture(Sale)

Industry(Sale)

Final Demand

Total sales

Agriculture(Purchase)

3

4

3

10

Industry(Purchase)

6

10

4

20

Consumer

1

6

Total Sales

10

20

Interpretation:

Out of the production of 10 of Agriculture Sector:

Agriculture Consumes 3 Units.

Industry Consumes 6 Units.

Consumer Consume 1 Unit.

Out of the Production of 20 of Industry:

Agriculture Consumes 4 units.

Industry consumes 10 units.

Consumer consumes 6 units.

B. Inter Sectoral Input and Output Transaction Matrix

Inter sectoral Input and Output Transaction Table

Agriculture(Sale)

Industry(Sale)

Agriculture(Purchase)

3

4

Industry(Purchase)

6

10

Inter sectoral Input and Output Transaction Matrix

A =

3 4

6 10

Interpretation- Agriculture Sector

Agriculture Sector sale to Agriculture Sector: 3 units

Agriculture Sector sale to Industry Sector: 6 Units

Interpretation – Industry Sector

Industry Sector Sale to Industry Sector: 10 units

Industry Sector sale to Agriculture sector: 4 units.

C. Inter Sectoral Input and Output Co-efficient

Inter Sectoral Input and Output Co-efficient Table

(Dividing column 1 by 10 and column 2 by 20)

Agriculture(Sale)

Industry(Sale)

Agriculture(Purchase)

0.3

0.2

Industry(Purchase)

0.6

0.5

Consumer

0.1

0.6

Interpretation – Agriculture Sector

Out of 1 unit total sale (Gross sale): Agriculture sale to Agriculture: 0.3, Agriculture sale to Industry: 0.6,

Interpretation – Industry Sector

Out of 1 unit total sale (Gross sale): Industry sale to Industry: 0.5, Industry sale to Agriculture: 0.2,

D. Sectoral direct output (input-output co-efficient matrix)

Table of Input-Output Coefficient

Agriculture(Sale)

Industry(Sale)

Agriculture(Purchase)

0.3

0.2

Industry(Purchase)

0.6

0.5

Input-Output Coefficient Matrix

A =

0.3 0.2 0.6 0.5

Interpretation:

Out of every 1 unit of gross output of agriculture sector 0.3 are used by the agriculture sector and 0.4 units by industry.

Out of every 1 unit of gross output industry sector 0.2 are used by the industry sector and 0.5 units by agriculture sector.


D. Direct and indirect output matrix (Input-output coefficient matrix)

Formula:

Intersectoral coefficient x Gross Production + Final output = Gross Output

[Matrix of intersectoral coefficients] x [Matrix of Gross Production] + [Matrix of Final Output] = [Matrix of Gross Production]

Where:

A: Matrix of intersectoral coefficients

X: Matrix of Gross Production

D: Matrix of Final Output

AX + D = X

1 0

0 1


If D =

AX + 1 = X

ð AX –X = -1

ð X – XA = 1

ð X(1-A) = 1

ð X = (1- A)-1


1 0

0 1

0.3 0.2 0.7 0.2

Now, (1 – A ) = =

0.6 0.5 0.6 0.5

Now, Cofactor Matrix of (1 – A )

0.5 0.6

=

0.2 0.7

Hence, Adjoin matrix of ( 1 – A )

0.5 0.2

=

0.6 0.7

Now, Determinants of ( 1 – A )

D = {0.35 – 0.12} = .23

1


D

Hence, Inverse Matrix of (1 – A )-1 = ------ x [Adjoin Matrix]

1

0.5 0.2

0.23

=----- x

0.6 0.7


2.17 0.87

=

2.61 3.04

If Industry and Agriculture Sector are 8 and 12 Respectively-

2.17 0.87 8

Then the matrix = X

2.61 3.04 12


27.8

=

57.36

Interpretation:

If agriculture and Industry factor are 8 and 12 Respectively

Then Gross Output of Agriculture 27.8 units

Gross Output of Industry 57.36 units

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